Given a list nums
and a positive integer k
, return the top k
frequent items from the list. A time complexity constraint is not given for this task.
Given an array n
of integers, find one peak in O(log*n)
time. A peak is defined as a number where the two numbers immediately left and right are strictly less than the number. Numbers outside of the bounds of this array are considered to be smaller.
Create a stack implementation that is able to return the minimum element as well as push
and pop
elements, all in constant time O(1)
.
Given a perfect binary search tree, connect all the nodes to the node on their right The solution is to do breadth-first-search in an iterative fashion. This puts all the nodes at the same level in a queue. By iterating over the queue we can connect each node to its successor. During this process we add the children of each node as the next entry. We repeat this process until the queue is empty.
Given a strictly positive integer n
, write a function that returns all possible combinations of well-formed parentheses.
Parentheses can be nested and added one after the other. It is important that we don’t create invalid combinations, such as )(
. The idea then becomes to start with a single set of parentheses ()
. We can add another set of parentheses at three possible places: 1(2)3
. When looking closely, we see that 1
and 3
are the same position.
We can then utilize Pythons string splitting capabilities which allow us to insert one or more characters at any place in the string. We do this by iterating over the string and inserting ()
at every possible position. This creates all valid pairs like (())
and ()()
etc.
To avoid the aforementioned duplicates we can add a memory to the function and store all the visited possible combinations. This allows us to speed the process up significantly. For example when we visit ()()
, we don’t need to visit it again to form ()()()
or ()(())
(for n=3
) because they would already been visited.